Monday, 11 September 2017

HSST CS QP 2011 - Part 4



4 comments:

  1. Answers

    48. A & D
    49. B
    50. D
    51. B
    52. A
    53. C
    54. C
    55. Question Incomplete
    56. C
    57. B, D
    58. B
    59. B
    60. D
    61. B
    62. B
    63. C
    64. C

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  2. 48. Explanation:

    Option D is true. But it also implies that option A is true. Because twice of any number must be even.

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  3. 57. Explanation:

    NAND and NOR operations are commutative, but not associative.

    (x↓y)↓z ≠ x↓(y↓z) (↓ = NOR operation)
    (x↑y)↑z ≠ x↑(y↑z) (↑ = NAND operation)

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  4. 58. Explanation:

    A universal gate is one from which all other basic gates can be formed. NAND and NOR are Universal gates.

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